Benutzer:Stargaming/Energie

Quelle	Natururan	Steinkohle	Braunkohle	Erdöl	Erdgas
Masse	1 kg	18.9 t	56,7 t	12,6 m3	14000,1 m3
Quelle: Online-Rechner des Informationskreises KernEnergie

${\begin{matrix}{\mathsf {Gegeben\!:}}&\rho &=&{\frac {m}{V}}\\&\rho _{uran}&=&18950{\frac {kg}{m^{3}}}\\&\rho _{bkohle}&=&1000{\frac {kg}{m^{3}}}\\&s_{\Box }&=&{\sqrt[{3}]{V}}\\{\mathsf {Gesucht\!:}}&V_{uran}\\&s_{uran}\\&s_{bkohle}\\\end{matrix}}$ Quellen: Braunkohle Uran

${\begin{matrix}\rho &=&{\frac {m}{V}}&\vert \times {\frac {V}{\rho }}\\V&=&{\frac {m}{\rho }}\\V_{uran}&=&{\frac {1kg}{18950{\frac {kg}{m^{3}}}}}\\V_{uran}&=&{\frac {1}{18950}}\,m^{3}\\V_{uran}&=&0{,}0000527704485\,m^{3}\\V_{uran}&=&0{,}0527704485\,dm^{3}\\V_{uran}&=&52{,}7704485\,cm^{3}\\s&=&{\sqrt[{3}]{V\,}}\\s_{uran}&=&{\sqrt[{3}]{V_{uran}}}\\s_{uran}&=&{\sqrt[{3}]{52{,}7704485\,cm^{3}}}\\s_{uran}&=&3{,}750854882\,cm\\\\V_{bkohle}&=&{\frac {56{,}7t}{1000{\frac {kg}{m^{3}}}}}\\V_{bkohle}&=&{\frac {56{,}7t}{1{\frac {t}{m^{3}}}}}\\V_{bkohle}&=&56{,}7\,m^{3}\\s_{bkohle}&=&{\sqrt[{3}]{56{,}7\,m^{3}}}\\s_{bkohle}&=&3{,}841737495\,m\\\end{matrix}}$