G e g e b e n : ρ = m V ρ u r a n = 18950 k g m 3 ρ b k o h l e = 1000 k g m 3 s ◻ = V 3 G e s u c h t : V u r a n s u r a n s b k o h l e {\displaystyle {\begin{matrix}{\mathsf {Gegeben\!:}}&\rho &=&{\frac {m}{V}}\\&\rho _{uran}&=&18950{\frac {kg}{m^{3}}}\\&\rho _{bkohle}&=&1000{\frac {kg}{m^{3}}}\\&s_{\Box }&=&{\sqrt[{3}]{V}}\\{\mathsf {Gesucht\!:}}&V_{uran}\\&s_{uran}\\&s_{bkohle}\\\end{matrix}}} Quellen: Braunkohle Uran ρ = m V | × V ρ V = m ρ V u r a n = 1 k g 18950 k g m 3 V u r a n = 1 18950 m 3 V u r a n = 0,000 0527704485 m 3 V u r a n = 0,052 7704485 d m 3 V u r a n = 52,770 4485 c m 3 s = V 3 s u r a n = V u r a n 3 s u r a n = 52,770 4485 c m 3 3 s u r a n = 3,750 854882 c m V b k o h l e = 56 , 7 t 1000 k g m 3 V b k o h l e = 56 , 7 t 1 t m 3 V b k o h l e = 56 , 7 m 3 s b k o h l e = 56 , 7 m 3 3 s b k o h l e = 3,841 737495 m {\displaystyle {\begin{matrix}\rho &=&{\frac {m}{V}}&\vert \times {\frac {V}{\rho }}\\V&=&{\frac {m}{\rho }}\\V_{uran}&=&{\frac {1kg}{18950{\frac {kg}{m^{3}}}}}\\V_{uran}&=&{\frac {1}{18950}}\,m^{3}\\V_{uran}&=&0{,}0000527704485\,m^{3}\\V_{uran}&=&0{,}0527704485\,dm^{3}\\V_{uran}&=&52{,}7704485\,cm^{3}\\s&=&{\sqrt[{3}]{V\,}}\\s_{uran}&=&{\sqrt[{3}]{V_{uran}}}\\s_{uran}&=&{\sqrt[{3}]{52{,}7704485\,cm^{3}}}\\s_{uran}&=&3{,}750854882\,cm\\\\V_{bkohle}&=&{\frac {56{,}7t}{1000{\frac {kg}{m^{3}}}}}\\V_{bkohle}&=&{\frac {56{,}7t}{1{\frac {t}{m^{3}}}}}\\V_{bkohle}&=&56{,}7\,m^{3}\\s_{bkohle}&=&{\sqrt[{3}]{56{,}7\,m^{3}}}\\s_{bkohle}&=&3{,}841737495\,m\\\end{matrix}}}